Answer
$r=\dfrac{6}{1+\sin \theta}$
Work Step by Step
From the given statement , we have: Directrix , $a=6$ above the pole and eccentricity ; $e=1$
The equation must be of the form as follows: $r=\dfrac{ae}{1-e \sin \theta}$
Then, we have $r=\dfrac{(1)(6)}{1+(1) \sin \theta}$
Therefore, $r=\dfrac{6}{1+\sin \theta}$
