Precalculus (6th Edition)

by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie

Published by Pearson

ISBN 10: 013421742X

ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Test - Page 1086: 25

Answer

$0.201$

Work Step by Step

Use binomial distribution with $n=6,p=\frac{1}{6}$ for $x=2$, we have $P(2)=\binom 6 2 p^2(1-p)^{6-2}=15(\frac{1}{6})^2(\frac{5}{6})^4\approx0.201$

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