Answer
$ \begin{bmatrix} 4 & 8 &-10 \end{bmatrix}$
Work Step by Step
Consider $A=\begin{bmatrix} 0 & 3 & -4 \end{bmatrix} $ and $B=\begin{bmatrix} -2 & 6 & 3 \\ 0 &4 & 2\\ -1& 1& 4\end{bmatrix} $
Since, the dimensions of matrix $A$ is $1 \times 3$ and that of matrix $B$ is $3 \times 3$. Therefore, the number of columns of matrix-$A$ will be same as the number of rows of the matrix-$B$ and so, we can take their product $AB$.
$AB=\begin{bmatrix} (0)(-2)+(3)(0)+(-4)(-1) & (0)(6)+(3)(4)+(-4)(1) & (0)(3)+(3)(2)+(-4)(4) \end{bmatrix}$
$ \\ =\begin{bmatrix} 0+0+4 & 0+12 -4 & 0+6-8 \end{bmatrix} \\= \begin{bmatrix} 4 & 8 &-10 \end{bmatrix}$
