Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 20: 33

Answer

$$\frac{-6}{7}$$

Work Step by Step

$$\frac{-8+(-4)(-6)\div12}{4-(-3)}$$ $$\frac{-8+24\div12}{7}$$ $$\frac{-8+2}{7}$$ $$\frac{-6}{7}$$
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