Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 23: 136

$158.3$

A “perfect” passer rating happens when we have $\frac{C}{A}=0.775, \frac{T}{A}=0.11875, \frac{Y}{A}=12.5, \frac{I}{A}=0 $, use the formula, we have $Rating = \frac{250\cdot 0.775+1000\cdot 0.11875+12.5\cdot 12.5+6.25-0}{3}\approx158.3$