Answer
$\color{blue}{\dfrac{4}{x}}
$
Work Step by Step
Cancel the common factors first before performing the actual multiplication to obtain:
$\require{cancel}
=\dfrac{2x}{5} \cdot \dfrac{2(5)}{x(x)}
\\=\dfrac{2\cancel{x}}{\cancel{5}} \cdot \dfrac{2(\cancel{5})}{x\cancel{(x)}}
\\=\dfrac{2}{1} \cdot \dfrac{2}{x}
\\=\color{blue}{\dfrac{4}{x}}
$
