Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises - Page 65: 106

Answer

$q-p$

Work Step by Step

Multiply $\frac{pq}{pq}$ to the expression, we have: $\frac{p^{-1}-q^{-1}}{(pq)^{-1}}=\frac{p^{-1}-q^{-1}}{(pq)^{-1}}\cdot\frac{pq}{pq}=\frac{q-p}{1}=q-p$
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