Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 74: 3

Answer

(a) to F (b) to H (c) to G (d) to C

Work Step by Step

(a) to F $(-3x)^{1/3}=\sqrt[3] {-3x}$ (b) to H $(-3x)^{-1/3}=\frac{1}{\sqrt[3] {-3x}}$ (c) to G $(3x)^{1/3}=\sqrt[3] {3x}$ (d) to C $(3x)^{-1/3}=\frac{1}{\sqrt[3] {3x}}$
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