Answer
$x$-intercepts: $3$ and $-3$
$y$-intercept: $-9$
Work Step by Step
The $x$-intercepts of an equation can be obtained by plugging $y=0$ into the equation, then solving for $x$ in the resulting equation..
Here we'd have:
$0=x^2-9$
$9=x^2$
$\pm\sqrt9=\sqrt{x^2}$
$\pm3=x$
Therefore there are two $x$-intercepts: $3$ and $-3$.
The $y$-intercepts of an equation can be obtained by plugging $x=0$ into the equation then solving for $y$ in the resulting equation .
Here we have:
$y=(0)^2-9$
$y=-9$
Therefore the $y$-intercept: $-9$.
