Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 1 - Functions and Their Graphs - Section 1.3 Properties of Functions - 1.3 Assess Your Understanding - Page 76: 63

Answer

(a). $17$, (b). $-1$, (c). $11$.

Work Step by Step

(a). From $x_1=-3$ to $x_2=-2$, we have the average rate of change as $\frac{g(x_2)-g(x_1)}{x_2-x_1}=\frac{((-2)^3-2(-2)+1)-((-3)^3-2(-3)+1)}{-2+3}=17$, (b). From $x_1=-1$ to $x_2=1$, we have the average rate of change as $\frac{g(x_2)-g(x_1)}{x_2-x_1}=\frac{((1)^3-2(1)+1)-((-1)^3-2(-1)+1)}{1+1}=-1$, (c). From $x_1=1$ to $x_2=3$, we have the average rate of change as $\frac{g(x_2)-g(x_1)}{x_2-x_1}=\frac{((3)^3-2(3)+1)-((1)^3-2(1)+1)}{3-1}=11$.
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