Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 1 - Functions and Their Graphs - Section 1.4 Library of Functions; Piecewise-defined Functions - 1.4 Assess Your Understanding - Page 86: 46

Answer

a) $0 $ b) $0 $ c) $-1$

Work Step by Step

We are given: $f(x)=int(2x)$ Note that the notation $int (x)$ means: the largest integer that is less than or equal to $x$. We simplify the given equation by substituting the $x$ values into the equation. $a) f(1.2)=int [\dfrac{(1.2)}{2}]=int (0.6)=0 \\ b) f(1.6)=int [\dfrac{(1.6)}{2}]=int (0.8)=0 \\ c) f(-1.8)=int(\dfrac{(-1.8)}{2}=int(-0.9)=-1 $
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