Answer
x-intercept $(-36,0)$. y-intercept $(0,\pm2)$. symmetry with respect to the x-axis only.
Work Step by Step
1. Let $y=0$, we have x-intercept $x=-36$ or $(-36,0)$. Let $x=0$, we have y-intercept $y=\pm2$ or $(0,\pm2)$.
2. To test symmetries, replace $(x,y)$ with $(x,-y)$ (x-axis symmetry), or $(-x,y)$ (y-axis symmetry), or $(-x,-y)$ (origin symmetry),
3. With the $y^2$ term, we can find the equation has a symmetry with respect to the x-axis only.
