Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.2 Graphs of Equations in Two Variables; Intercepts; Symmetry - F.2 Assess Your Understanding - Page 17: 71

Answer

Refer to the graph below.

Work Step by Step

In order to sketch the graph, we should first look at the $(x,y)$ coordinates that satisfy the equation. We can get some of these points by assinging values tio $x$ then slving for the corresponding value of $y$ for each value of $x$. If $x=0$, then $y=\sqrt0=0$. Thus, $(0,0)$ is on the graph. If $x=1$, then $y=\sqrt1=1$. Thus, $(1,1)$ is on the graph. If $x=4$, then $y=\sqrt4=2$. Thus, $(4,2)$ is on the graph. If $x=9$, then $y=\sqrt9=3$. Thus, $(9,3)$ is on the graph. Plot these points and connect them using a smooth curve to complete the graph, Refer to the graph above.
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