Answer
(a) $(-9,0)$, $(0,\pm3)$, (b) symmetric with respect to the x-axis. (c) See graph.
Work Step by Step
(a) Given $x-y^2=-9$, we can find the x-intercept(s) (let y=0) as $(-9,0)$, y-intercept(s) (let x=0) as $(0,\pm3)$,
(b) To test symmetry, replace $(x,y)$ with $(x,-y)$ (x-axis symmetry), or $(-x,y)$ (y-axis symmetry), or $(-x,-y)$ (origin symmetry), and due to the $y^2$ term, we can find the equation is symmetric with respect to the x-axis.
(c) See graph.
