Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.3 Lines - F.2 Assess Your Understanding - Page 33: 143

Answer

The student is wrong. The student forgot to leave the negative sign on the nominator, resulting to a positive slope. The correct slope is $-\frac{3}{2}$.

Work Step by Step

The slope of the line can be calculated with the formula: d $m=\frac{y_2-y_1}{x_2-x_1}$, where the two points on the line are $(x_1,y_1)$ and $(x_2,y_2)$ Here, the calculation should be: $m=\dfrac{-4-2}{1-(-3)}=\dfrac{-6}{4}=-\dfrac{3}{2}$ Thus, the student is wrong as he/she forgot to leave the negative sign on the nominator, resulting in a positive slope.
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