Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.10 - Lines - 1.10 Exercises - Page 114: 4

Answer

x-intercept: 6 y-intercept: 4 slope = $-\frac{2}{3}$

Work Step by Step

RECALL: x-intercept can be found by setting y=0 y=intercept can be found by setting x =0 x-intercept Set $y=0$ to have: $2x+3(0) -12 = 0 \\2x-12=0 \\2x=12 \\x=6$ Thus, the x-intercept is 6. y-intercept Set $x=0$ to have: $2(0) +3y-12=0 \\3y-12=0 \\3y=12 \\y=4$ Thus, the y-intercept is 4. RECALL: The slope-intercept form of the equation of a line is $y=mx+b$ where m=slope and b=y-intercept. Write the given equation in slope-intercept form by isolating $y$ to have: $2x+3y-12=0 \\3y=-2x+12 \\y=\frac{-2x+12}{3} \\y=-\frac{2}{3}x + 4$ Thus, the line has a slope of $-\frac{2}{3}$.
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