Answer
Rationalizing a denominator means eliminating the radical in the denominator.
$\frac{1}{\sqrt 3}$=$\frac{1}{\sqrt 3}$$\times$$\frac{\sqrt 3}{\sqrt 3}$= $\frac{\sqrt 3}{3}$
Work Step by Step
If we have $\frac{1}{\sqrt[n]{a^{m}}}$ we should multiply both numerator and denominator by $\sqrt[n]{a^{n-m}}$ which is equivalent to multiplying by one. so for $\sqrt[2]{3^1}$ we should multiply both numerator and denominator by $\sqrt[2]{3^{2-1}} = \sqrt{3}$. After that, we obtain a standard form.
