Answer
(a) $500^{2}-1^{2}$
(b) $70^{2}-9^{2}$
(c) $2000^{2}-7^{2}$
Work Step by Step
(a) $501\times499=(500+1)\times(500-1)=500^{2}-1^{2}$
(b) $79\times61=(70+9)\times(70-9)=70^{2}-9^{2}$
(c) $2007\times1993=(2000+7)\times(2000-7)=2000^{2}-7^{2}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises - Page 35: 139
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