Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.7 - Modeling with Equations - 1.7 Exercises - Page 80: 89

Answer

Height of the structure is $18ft$

Work Step by Step

We know the total volume, that is $1400\pi ft^3$. It is sum of volume of the cone and the cylinder. (Note, height of only cylinder is $\frac{2}{3}h$) $V_{cylinder}=\pi r^2 h = \frac{200\pi h}{3}$ $V_{cone}=\frac{\pi r^2 h}{3}=\frac{100\pi \frac{1}{3}h}{3}=\frac{100\pi h}{9}$ $\frac{200\pi h}{3}+\frac{100\pi h}{9} = 1400\pi$ $600\pi h + 100\pi h =12600\pi$ $700\pi h = 12600\pi$ $h=\frac{12600\pi}{700\pi}=18ft$
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