Precalculus: Mathematics for Calculus, 7th Edition

by Stewart, James; Redlin, Lothar; Watson, Saleem

Published by Brooks Cole

ISBN 10: 1305071751

ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.4 - Average Rate of Change of a Function - 2.4 Exercises - Page 188: 18

Answer

a) $-16$ b) $-4$

Work Step by Step

a) $g(-2)=(-2)^4-(-2)^3+(-2)^2=16+8+4=28$ $g(2)=(2)^4-(2)^3+(2)^2=16-8+4=12$ $12-28=-16$ b) $\frac{12-28}{2-(-2)}=-4$

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