Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.4 - Average Rate of Change of a Function - 2.4 Exercises - Page 190: 37

Answer

a) $10m/s$ b) We can see that the winner A has started with high speed and with negative acceleration , so the speed gets decreased with time. Winner B skied with has started with the constant speed, thus no acceleration. Winner C has started with low speed and with positive acceleration , so the speed gets increased with time.

Work Step by Step

a) The average speed is given by $Speed_{avg.}=\dfrac{Distance}{Time}$ Thus, we have $Speed_{avg.}=\dfrac{Distance}{Time}=\dfrac{100}{10}=10 m/s$ b) We can see that the winner A has started with high speed and with negative acceleration , so the speed gets decreased with time. Winner B skied with has started with the constant speed, thus no acceleration. Winner C has started with less speed and with positive acceleration , so the speed gets increased with time.
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