Answer
$x+2 +\frac{8}{x-3}$
Work Step by Step
By using long division to solve the equation it will go as follows. $x$ goes into $x^2$, $x$ times.
($x^2 -5x$) - ($x^2 -3x$)
Your remainder here is $2x$. $x$ goes into $2x$, $2$ times.
($2x+2$) - ($2x-6$)
Your final remainder is 8.
Therefore your answer is $x+2 +\frac{8}{x-3}$ (your remainder goes over your divisor).
