Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.1 - Polar Coordinates - 8.1 Exercises - Page 593: 57

Answer

$x^2+(y-2)^2=4$

Work Step by Step

To solve this one multiply both sides by r. We get $r^2=4rsin(t)$. We can rewrite that as $x^2+y^2=4y$ since $r^2=x^2+y^2$ and $rsin(t)=y$. Thus the equation becomes $x^2+(y-2)^2=4$.
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