Answer
$40$ outcomes
Work Step by Step
A is set of 5-cards consecutive in denomination
B is set of 5-cards which are from same suit
$A\cap B$ will be set of 5-cards which are both consecutive and belong to the same suit.
Now counting outcomes of $A\cap B$
There are 4 suits in deck of 52 cards each with 13 cards
There can be 10 outcomes for 5-consecutive cards from a particular suit
$1^{st}$ outcome - (A,2,3,4,5)
$9^{th}$ outcome - (9, 10, A, J, Q)
$10^{th} outcome - (10,A, J, Q, K)
So from suits we will get $4*10=40 such outcomes because there are $4$ types of suits.
