Answer
a) $0.4$
b) $0.8$
c) $0.6$
d) $1$
e) $0.2$
Work Step by Step
a) A = {a, b, c} , so $P(A) = 0.1 + 0.1 + 0.2 = 0.4$
b) B = {c, d, e} , so $P(B) = 0.2 + 0.4 + 0.2 = 0.8$
c) $P(A') = 1 - P(A) = 1 - 0.4 = 0.6$
d) $A\cup B$ = {a, b, c, d, e} , which is the whole set of outcomes.
That means that $P(A\cup B)$ must equal $1$
e) $A\cap B$ = {c} , so $P(A\cap B) = 0.2$
