Answer
$0.014$
Work Step by Step
Let F be the event that the fails and W be the event that the connector is wet. Then using the rule of total probability for $2$ events, $P(F)=P(F\cap W)+P(F\cap W')\\=P(F|W)P(W)+P(F|W')P(W')\\=0.05\cdot0.1+0.01\cdot0.9\\=0.005+0.009=0.014$