Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 1 - Introduction to Statistics - Review - Cumulative Review Exercises - Page 38: 7

Answer

$28$

Work Step by Step

We calculate the result:$\frac{(96-100)^{2}+(106-100)^{2}+(98-100)^{2}}{3-1}=\frac{16+36+4}{2}=28$.
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