Answer
$0.0444$.
Work Step by Step
To solve this problem, we can find the z-scores associated with $0.67Q_1$ and $1.5Q_3$. Doing this and checking the table of z-scores, we can find that the probability of an outlier is $0.0444$.
Elementary Statistics (12th Edition)
by Triola, Mario F.
Published by
Pearson
ISBN 10:
0321836960
ISBN 13:
978-0-32183-696-0
Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Beyond the Basics - Page 271: 37
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