Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

by Bluman, Allan

Published by McGraw-Hill Education

ISBN 10: 0078136334

ISBN 13: 978-0-07813-633-7

Chapter 4 - Probability and Counting Rules - 4-3 The Multiplication Rules and Conditional Probability - Exercises 4-3 - Page 225: 39

Answer

0.574

Work Step by Step

First find the case that all 5 are on time; $p=0.843^5=0.426$ so the case that at least 1 was not on time is: $1-0.426=0.574$

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