Answer
n = 10, df = 10-1=9, α = 1-0.90 = 0.1
To find χ2 right ,
α/2=0.05
From the table,
χ2 right =16.919
To find χ2 left,
1-0.05=0.95
From the table,
χ2 left =3.325
The Confidence Interval for a Variance:
$ \frac{(n-1)s^2}{χ2 right}$ < $σ^{2}$ < $ \frac{(n-1)s^2}{ χ2 left}$
$ \frac{9*4.1^2}{21.666}$ < $σ^{2}$ < $ \frac{5*4.1^2}{3.325}$
= 5.0179 < $σ^{2}$ < 204.0049