Answer
A. Class width = 11
B. Class midpoints = 25,36,47,589,69,80,91
C. Class boundaries = (19.5-30.5), (30.5-41.5), (41.5-52.5), (52.5-63.5), (63.5-74.5), (74.5-85.5), (85.5-96.5)
Work Step by Step
A. Using the table, find the difference between either two sequential lower class limits, or two sequential upper class limits (i.e. 31-20, or 41-30)
B. add one set of classes and divide by two. (i.e, [20+30]/2=25)
C. -.5 to lower class boundary, +.5 to upper class boundary
