Answer
Classes with greatest frequency: 198 - 281; frequency = 8
Classes with least frequency: 282 -365 ; frequency = 2
Work Step by Step
1. The number of classes (6) as stated.
2. The minimum data entry is 30 and the maximum data entry is 530, so the range is $530 - 30 = 500$. Class width = range/number of classes: $500/6 = 83.333 ≈ 84 $.
3. The minimum data of 30 entry is a convenient lower limit for the first class. Find the lower limits of the remaining 5 classes, add the class width of 84 to the lower limit of each previous class. So, the lower limits of the other classes are 30 + 84 = 114, 114 + 84 = 198, and so on. The upper limit of the first class is 113 which is one less than the lower limit of the second class. The upper limits of the other classes are 113 + 84 = 15, 197 + 84 = 281, and so on
4. Tallying is the done for each data entry in the appropriate class.
5. Midpoint = (Lower class limit) + (Upper class limit) /2, So, midpoint of first class $(30+113)/2 = 71.5 $ and so on.
6. To find the relative frequency of a class, divide the frequency ,f by the sample size n. Relative frequency for the first Class frequency Sample size $5/29 = 0.17$ and so on.
7. The cumulative frequency of a class is the sum of the frequencies of that class and all previous classes. The cumulative frequency of the last class is equal to the sample size n.
8. The frequency distribution is shown below
