Answer
(a) z ≈ 1.15
(b) An age of 32 is about 1.15 standard deviations above
the mean.
(c) Not unusual
Work Step by Step
z = (x - μ) / σ = (32-28.1) / 3.4 = 1.15
Usual values have z score in the range -2 and 2.
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