Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 3 - Section 3.1 - Measures of Center for Ungrouped Data - Exercises - Page 88: 3.13

Answer

Mean = 429.8 Median = 103.5 No mode 10% Trimmed mean = 124 Trimmed mean is the best way to measure these data.

Work Step by Step

a. Mean = $(45+68+77+82+99+108+127+153+278+3261)\div10 = 429.8$ Median = $(5th + 6th)\div2= (99+108)\div2=103.5$ b.There is no mode in these data sets, because each data occurs only once. c. 10% trimmed mean = 10% of 10 values = 10(0.10) = 1, therefore we drop one value from each end of the ranked data. $(68+77+82+99+108+127+153+278)\div8 = 124$ d. Trimmed mean is suggested because these data contain outliers; trimmed mean can eliminate the outlier and have a better representation of data.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.