Answer
a. Range = 26, Variance = 75.64, Standard of Deviation = 8.6971
b. Coefficient of Variation = 35.64%
c. The high values of standard deviation indicate that the values of that data set are spread over a larger range around the mean.
Work Step by Step
a. Range = Highest value- Lowest value = 39-13 = 26
Variance = $σ^2=(∑〖(x-μ)〗^2 )/N $
$=[∑(x^2) -∑(x)^2]/10/N$
$=[6710-5953.6]/10$
$=75.64$
Standard Deviation = $\sqrt 75.64= 8.6971$
b. Coefficient of Variation = $8.6971\div24.4 \times100% = 35.64%$
