Statistics for the Life Sciences (5th Edition)

Published by Pearson
ISBN 10: 0-32198-958-9
ISBN 13: 978-0-32198-958-1

Chapter 4 - The Normal Distribution - Supplementary Exercises 4.S.1 - 4.S.21 - Page 144: 4.S.4

Answer

(a) 97.98% (b) 12.71% (c) 46.39% (d) 10.69% (e) 35.51% (f) 5.59% (g) 59.10%

Work Step by Step

You will need this formula $z=(y−μ)/σ$ Where y = the point of intrest μ = the mean of the data set σ = the standard deviation of the data set *Please refer to table 3 for the Standard Normal Cumulative Probability Table The heights of a certain population of corn plants follow a normal distribution with mean 145 cm and standard deviation 22 cm. What percentage of the plants heights are (a) 100 cm or more? $-2.05=(100−145)/22$ $-2.05 = 0.0202$ $1 - 0.0202 = 0.9798$ (b) 120 cm or less? $-1.14=(120−145)/22$ $-1.14 = 0.1271$ (c) between 120 and 150 cm? $-1.14=(120−145)/22$ $0.23=(150−145)/22$ $0.23 = 0.5910$ $-1.14 = 0.1271$ $0.5910 - 0.1271 = 0.4639$ (d) between 100 and 120 cm? $-1.14=(120−145)/22$ $-2.05=(100−145)/22$ $-2.05 = 0.0202$ $-1.14 = 0.1271$ $0.1271 - 0.0202 = 0.1069$ (e) between 150 and 180 cm? $0.23=(150−145)/22$ $1.59=(180−145)/22$ $1.59 = 0.9441$ $0.23 = 0.5910$ $0.9441 - 0.5910 = 0.3551$ (f) 180 cm or more? $1.59=(180−145)/22$ $1.59 = 0.9441$ $1 - 0.9441 = 0.0559$ (g) 150 cm or less? $0.23=(150−145)/22$ $0.23 = 0.5910$
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