Answer
We fail to reject the null hypothesis. Thus we do not have enough evidence to conclude that the machine should be re-calibrated.
Work Step by Step
Here we have: n = 36, x̅ = 0.876, s = 0.005 and α = 0.01
Using the classical approach:
Using Table-VI, we have: $ t_{0.01} = 2.438$
$t = \frac{0.876 - 0.875}{0.005/\sqrt 36} = 0.001/0.0008 = 1.2$
Since 1.2 < 2.438, we fail to reject the Null Hypothesis.
