Answer
We fail to reject the null hypothesis. Hence, we will refute this headline.
Work Step by Step
Here we have $H_{o}$: p = 0.65, $H_{a}: p < 0.65$, n = 1025, p = 0.0.65, $\hat p =653/1025 = 0.637$
Checking model requirements:
np(1-p) = 1025 x 0.65 (1 - 0.65) = 233.19 > 10
$z = \frac{0.637 - 0.65}{\sqrt \frac{0.65(1-0.65)}{1025}} = -0.873$
$P(z \lt -0.873) = 0.1913 \gt 0.05$
We fail to reject the null hypothesis.
