Answer
Since we have rejected the Null hypothesis in favor of the Alternate Hypothesis, we have sufficient evidence to support the claim that the class is effective.
Work Step by Step
Here we have $H_{o}$: μ = 198, $H_{1}$: μ > 198, n = 10, x̅ = 208.4, s = 9.38 and α = 0.01
Using the Classical approach:
Using Table VI, we have: t = 1.383
$σ_{ x̅} = \frac{s}{\sqrt n} = \frac{9.38}{\sqrt 10} = 2.966$
$t = \frac{208.4 - 198}{2.966} = 3.506$
Since, 3.506 > 1.383, we will reject the Null hypothesis.
