Answer
$F_0=5.64$ with a P-value $\ltα$. Reject the null hypothesis.
There is enough evidence to conclude that the standard deviation of acidity in the rain near Houston, Texas, is different from that near Chicago, Illinois.
Work Step by Step
$H_0:~σ_{Texas}=σ_{Illinois}$ versus $H_1:~σ_{Texas}\neσ_{Illinois}$
In MINITAB, enter the Texas values in C1 and the Illinois values in C2.
Select Stat -> Basic Statistics -> 2 Variances
Select "Each sample is in its own column"
In Sample 1 enter C1 and in Sample 2 enter C2
Click in Options. In "Ratio" select (sample variance 1)/(sample variance 2). Enter 95 in Confidence level, 1 in Hypothesized ratio. In "Alternative hypothesis" select "Difference $\ne$ hypothesized ratio". Select "Use test and confidence intervals based on normal distribution". Click OK.
Click OK.
$F_0=5.64$ with a P-value $=0.004\lt0.05=α$
