Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 11 - Section 11.1 - Assess Your Understanding - Applying the Concepts - Page 542: 35

Answer

$z_0\gt z_{\frac{α}{2}}$: null hypothesis is rejected. There is enough evidence to conclude that the remapped network has a different proportion of errors than the neural network.

Work Step by Step

$H_0:~p_1=p_2$ versus $H_1:~p_1\ne p_2$ $z_0=\frac{|f_{12}-f_{21}|-1}{\sqrt {f_{12}+f_{21}}}=\frac{|385-456|-1}{\sqrt {385+456}}=2.41$ $z_{\frac{α}{2}}=z_{0.025}$ If the area of the standard normal curve to the right of $z_{0.025}$ is 0.025, then the area of the standard normal curve to the left of $z_{0.025}$ is $1−0.025=0.975$ According to Table V, the z-score which gives the closest value to 0.975 is 1.96. Since $z_0\gt z_{\frac{α}{2}}$, we reject the null hypothesis.
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