Answer
$z_0\gt z_{\frac{α}{2}}$: null hypothesis is rejected.
There is enough evidence to conclude that the proportion of healthy people and the proportion of happy people differ.
According to the table, there are more happy who are not healthy than healthy people who are not happy.
Work Step by Step
$H_0:~p_1=p_2$ versus $H_1:~p_1\ne p_2$
$z_0=\frac{|f_{12}-f_{21}|-1}{\sqrt {f_{12}+f_{21}}}=\frac{|123-70|-1}{\sqrt {123+70}}=3.74$
$z_{\frac{α}{2}}=z_{0.025}$
If the area of the standard normal curve to the right of $z_{0.025}$ is 0.025, then the area of the standard normal curve to the left of $z_{0.025}$ is $1−0.025=0.975$
According to Table V, the z-score which gives the closest value to 0.975 is 1.96.
Since $z_0\gt z_{\frac{α}{2}}$, we reject the null hypothesis.
