Answer
$X^2\gt X_α^2$: null hypothesis is rejected.
There is enough evidence to conclude that bicycle deaths are not uniformly distributed over the days of the week.
Work Step by Step
$H_0:$ bicycle deaths are uniformly distributed.
versus
$H_1:$ bicycle deaths are not uniformly distributed.
Expected count of each of the 7 days: $200\times\frac{1}{7}=28.5714$
$X^2=Σ\frac{(O_i-E_i)^2}{E_1}=\frac{(16-28.5714)^2}{28.5714}+\frac{(35-28.5714)^2}{28.5714}+\frac{(16-28.5714)^2}{28.5714}+\frac{(28-28.5714)^2}{28.5714}+\frac{(34-28.5714)^2}{28.5714}+\frac{(41-28.5714)^2}{28.5714}+\frac{(30-28.5714)^2}{28.5714}=19.030$
$k=7$. So, $d.f.=7-1=6$
$X_α^2=X_{0.05}^2=12.592$
(According to Table VII, for d.f. = 6 and area to the right of critical value = 0.05)
Since $X^2\gt X_α^2$, we reject the null hypothesis.
