Answer
$F_0=7.50$ with a P-value $\ltα$. Reject the null hypothesis.
There is enough evidence to conclude that at least one population mean is different from the others.
Work Step by Step
$H_0:µ_1=µ_2=µ_3$ versus
$H_1:$ at least one population mean is different from the others
In MINITAB, enter the Front values in C1, the Middle values in C2 and in C3 enter the Back values.
Select Stat -> ANOVA -> One-Way
Select Response data are in a separate column for each factor level.
In Responses enter C1 C2 C3
Click Ok.
$F_0=7.50$ with a P-value $=0.003\ltα=0.05$
