Answer
$_{5}C_2=10$
Work Step by Step
For each pairwise we must select 2 from the 5 treatment levels.
$_nC_r=~_{5}C_2=\frac{5!}{2!\times(5-2)!}=\frac{5!}{2!\times3!}=\frac{120}{2\times6}=10$
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