Answer
$F_0=10.59$ with a P-value $\ltα$. Reject the null hypothesis.
We can conclude that al least one population mean is different from the others.
Work Step by Step
$H_0:µ_{87~Octane}=µ_{89~Octane}=µ_{92~Octane}$ versus
$H_1:$ at least one population mean is different from the others
In MINITAB, enter the data according to the table below.
Select Stat -> ANOVA -> General Linear Model -> Fit General Linear Model
In Responses enter C3. In Factores enter C1 C2.
Click Ok.
$F_0=10.59$ with a P-value $=0.003\ltα=0.05$
