Statistics: Informed Decisions Using Data (4th Edition)

by Sullivan III, Michael

Published by Pearson

ISBN 10: 0321757270

ISBN 13: 978-0-32175-727-2

Chapter 6 - Section 6.3 - Assess Your Understanding - Vocabulary and Skill Building - Page 351: 10a

Answer

$P(2)=0.184$

Work Step by Step

$P(x)=\frac{(λt)^{x}}{x!}e^{-λt}$ For λ = 0.02, t = 50 and x = 2 $P(2)=\frac{(0.02\times50)^{2}}{2!}e^{-0.02\times50}=\frac{1^2}{2}e^{-1}=0.184$

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