The Basic Practice of Statistics 7th Edition

by Moore, David S.; Notz, William I.; Fligner, Michael A.

Published by W. H. Freeman

ISBN 10: 146414253X

ISBN 13: 978-1-46414-253-6

Chapter 16 - Confidence Intervals: The Basics - Apply Your Knowledge - Page 382: 16.6

Answer

10.0161 to 10.1505

Work Step by Step

We find: $\frac{10.08 + 9.89 + 10.05 + 10.16 + 10.21 + 10.11}{6}$ = 10.0833

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