Answer
B, {$\frac{-5\pm\sqrt 7}{2}$}
Work Step by Step
Equation B is set up for the direct use of the square root property. This is because it is the of the form $(x-a)^{2}=k$ and equations of this form can be solved directly by the square root property.
$(2x+5)^{2}=7$
According to the square root property, $2x+5=\pm\sqrt 7$
Subtracting 5 from both sides, $2x+5-5=-5\pm\sqrt 7$
$2x=-5\pm\sqrt 7$
Dividing both sides by 2, $\frac{2x}{2}=\frac{-5\pm\sqrt 7}{2}$
Therefore, $x=\frac{-5\pm\sqrt 7}{2}$
The solution set of the equation is {$\frac{-5\pm\sqrt 7}{2}$}.
