Appendix C - Functions - Page 436: 57

(a) $f(-2)=0$ (b) $f(0)=4$ (c) $f(1)=2$ (d) $f(4)=4$

(a) To evaluate $f(-2)$ using the graph, we first find $-2$ on the x-axis. Normally, we would move vertically from this point on the x-axis until the graph is reached. However, since the graph already intersects $-2$ on the x-axis, the y-component of this intersected point is the required answer. The y-component of this point is $0$. Therefore, $f(-2)=0$. (b) To evaluate f(0) using the graph, we find $0$ on the x-axis. From $0$ on the x-axis, we move up vertically until the graph of f is reached. This point represents the required y-component. Therefore, $f(0)=4$. (c) To evaluate $f(1)$ using the graph, we find $1$ on the x-axis. From $1$ on the x-axis, we move up vertically until the graph of $f$ is reached. From this point, we then move horizontally towards the y-axis which gives a corresponding value of $2$. Therefore, $f(1)=2$. (d) To evaluate $f(4)$ using the graph, we find $4$ on the x-axis. From $4$ on the x-axis, we move up vertically until the graph of $f$ is reached. From this point, we then move horizontally towards the y-axis which gives a corresponding value of $4$. Therefore, $f(4)=4$.